b^2-14b-95=0

Solution for b^2-14b-95=0 equation:

Simplifying
b2 + -14b + -95 = 0

Reorder the terms:
-95 + -14b + b2 = 0

Solving
-95 + -14b + b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-5 + -1b)(19 + -1b) = 0

Subproblem 1
Set the factor '(-5 + -1b)' equal to zero and attempt to solve:

Simplifying
-5 + -1b = 0

Solving
-5 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '5' to each side of the equation.
-5 + 5 + -1b = 0 + 5

Combine like terms: -5 + 5 = 0
0 + -1b = 0 + 5
-1b = 0 + 5

Combine like terms: 0 + 5 = 5
-1b = 5

Divide each side by '-1'.
b = -5

Simplifying
b = -5
Subproblem 2
Set the factor '(19 + -1b)' equal to zero and attempt to solve:

Simplifying
19 + -1b = 0

Solving
19 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + -1b = 0 + -19

Combine like terms: 19 + -19 = 0
0 + -1b = 0 + -19
-1b = 0 + -19

Combine like terms: 0 + -19 = -19
-1b = -19

Divide each side by '-1'.
b = 19

Simplifying
b = 19
Solution
b = {-5, 19}